What matters

  • Compressor maps use absolute outlet pressure divided by absolute inlet pressure.
  • Twenty psi gauge boost is about 2.36 pressure ratio at standard sea-level pressure.
  • At lower atmospheric pressure, the same gauge boost requires a higher pressure ratio and usually more turbo speed.

Gauge pressure is not compressor pressure ratio

A boost gauge measures pressure above the surrounding atmosphere. Garrett defines compressor pressure ratio as absolute outlet pressure divided by absolute inlet pressure. Both sides of the ratio must use absolute pressure.

Pressure ratio = (gauge boost + atmospheric pressure) ÷ atmospheric pressure

Worked example at sea level

Using 14.7 psi as standard sea-level atmospheric pressure:

PR = (20 + 14.7) ÷ 14.7 = 2.36

The compressor outlet is operating at roughly 2.36 times the inlet absolute pressure, before accounting for pressure losses through the filter, intercooler, piping, and throttle system.

The same 20 psi at altitude

If local atmospheric pressure is approximately 12.2 psi, the same gauge target becomes:

PR = (20 + 12.2) ÷ 12.2 = 2.64

The driver sees the same 20 psi gauge reading, but the compressor must create a larger ratio. On a compressor map, that moves the operating point upward and can require more shaft speed and outlet temperature. Available mass flow and control strategy also change with air density.

Pressure ratio is only one map coordinate

A compressor map also needs corrected mass flow. Surge, choke, efficiency islands, and speed lines determine whether the operating point is sensible. Do not select a turbo or declare a boost level safe from pressure ratio alone; displacement, RPM, volumetric efficiency, temperature, fuel, exhaust backpressure, and hardware limits all matter.

Sources and methodology

Calculations are shown so the assumptions can be checked. Safety-critical fitment, fueling, and calibration decisions must be verified against current manufacturer documentation and the professional responsible for the work.